\input vanilla.sty \magnification=1200 \baselineskip=10pt \nopagenumbers \centerline{\bf Complex Analysis Preliminary Exam} \bigskip \centerline{\bf June 4, 1999} \bigskip \item{1.} Let $f$ be a complex-valued harmonic function in a domain $\Omega\subset {\bold{C}}$. Prove that if \newline $|f|$ = const in $\Omega$, then $f$ = const. \bigskip \item{2.} Let $f$ be a holomorphic function in the unit disk which is continuous up to the boundary of the disk ${\bold{T}}=\partial \Delta=\{z\in {\bold{C}}: |z|=1\}$. Prove that if $|f(z)|=1$ for all $z\in {\bold{T}}$, then $f$ is a rational function. \bigskip \item{3.} Let $f$ be an entire function such that Re$(f(z))\leq 0$ for all $z\in {\bold{C}}$. Prove that \newline $f$ = const. \bigskip \item{4.} For each real $t$ compute the integral $\varphi(t) = \dsize\int^\infty_{-\infty} \frac{e^{itx}}{1+x^2} dx$. \bigskip \item{5.} Construct a conformal mapping of the unit disk onto the crescent $$\{z\in {\bold{C}}: |z|<1, \ \ \Bigg|z-\frac{1}{2}\Bigg| \geq \frac{1}{2}\} \ .$$ \bigskip \item{6.} How many complex solutions does the equation $$z= \cos z$$ have? Justify your answer. \medskip {\underbar{Hint}}. Use the following fact: \medskip If an entire function $F(z)$ has no zeros and satisfies $$|F(z)| \leq C_1 e^{C_2|z|} \ \ (z\in {\bold{C}})$$ then $F(z) = e^{az+b}$. \bigskip \item{7.} Let $f$ be a bounded analytic function in the right half-plane. Prove that if $$f(n)=0 \ \text{for} \ n=1,2,3,\dots \ ,$$ then $f\equiv 0$. \bigskip \item{8.} Let $f_1,f_2$ be entire functions, and let $J$ be the set of all combinations $$A_1f_1 + A_2f_2,$$ where $A_1$ and $A_2$ are entire functions. Show that there exists an entire function $f$ such that $J$ consist of all entire functions $Af$, where $A$ is entire. \bigskip {\underbar{Hint}}: Use the result of Problem \#9. \medskip \item{9.} Let $\{a_n\}$ be a sequence in ${\bold{C}}$, $\dsize\lim_{n\to \infty} a_n=\infty$. Prove that for any sequence $\{b_n\}$ of complex numbers there exists an entire function $f$ such that $f(a_n)=b_n$. \bye