The following identity may be regarded as a formulation of the Weierstrass product for the Gamma function. $${\int }_0^{\infty }{t}^x{e}^{-t}\frac{dt}{t}=\frac{1}{x}\prod _{k=1}^{\infty }\frac{{\left(1+\frac{1}{k}\right)}^x}{\left(1+\frac{x}{k}\right)}$$ Understanding the derivation of this identity is reasonable for a bright student of first year undergraduate calculus in the United States.